9(c+2)-11=5(2c+3)-2c

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Solution for 9(c+2)-11=5(2c+3)-2c equation:


Simplifying
9(c + 2) + -11 = 5(2c + 3) + -2c

Reorder the terms:
9(2 + c) + -11 = 5(2c + 3) + -2c
(2 * 9 + c * 9) + -11 = 5(2c + 3) + -2c
(18 + 9c) + -11 = 5(2c + 3) + -2c

Reorder the terms:
18 + -11 + 9c = 5(2c + 3) + -2c

Combine like terms: 18 + -11 = 7
7 + 9c = 5(2c + 3) + -2c

Reorder the terms:
7 + 9c = 5(3 + 2c) + -2c
7 + 9c = (3 * 5 + 2c * 5) + -2c
7 + 9c = (15 + 10c) + -2c

Combine like terms: 10c + -2c = 8c
7 + 9c = 15 + 8c

Solving
7 + 9c = 15 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
7 + 9c + -8c = 15 + 8c + -8c

Combine like terms: 9c + -8c = 1c
7 + 1c = 15 + 8c + -8c

Combine like terms: 8c + -8c = 0
7 + 1c = 15 + 0
7 + 1c = 15

Add '-7' to each side of the equation.
7 + -7 + 1c = 15 + -7

Combine like terms: 7 + -7 = 0
0 + 1c = 15 + -7
1c = 15 + -7

Combine like terms: 15 + -7 = 8
1c = 8

Divide each side by '1'.
c = 8

Simplifying
c = 8

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