9(c+3)=8-(-9c-19)

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Solution for 9(c+3)=8-(-9c-19) equation: 



9(c+3)=8-(-9c-19)

We move all terms to the left:

9(c+3)-(8-(-9c-19))=0

We multiply parentheses

9c-(8-(-9c-19))+27=0



We calculate terms in parentheses: -(8-(-9c-19)), so:

8-(-9c-19)

determiningTheFunctionDomain
-(-9c-19)+8

We get rid of parentheses

9c+19+8

We add all the numbers together, and all the variables

9c+27

Back to the equation:

-(9c+27)



We get rid of parentheses

9c-9c-27+27=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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