9(c-1)=6(b+2)-a

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Solution for 9(c-1)=6(b+2)-a equation:


Simplifying
9(c + -1) = 6(b + 2) + -1a

Reorder the terms:
9(-1 + c) = 6(b + 2) + -1a
(-1 * 9 + c * 9) = 6(b + 2) + -1a
(-9 + 9c) = 6(b + 2) + -1a

Reorder the terms:
-9 + 9c = 6(2 + b) + -1a
-9 + 9c = (2 * 6 + b * 6) + -1a
-9 + 9c = (12 + 6b) + -1a

Reorder the terms:
-9 + 9c = 12 + -1a + 6b

Solving
-9 + 9c = 12 + -1a + 6b

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 9c = 12 + -1a + 9 + 6b

Combine like terms: -9 + 9 = 0
0 + 9c = 12 + -1a + 9 + 6b
9c = 12 + -1a + 9 + 6b

Reorder the terms:
9c = 12 + 9 + -1a + 6b

Combine like terms: 12 + 9 = 21
9c = 21 + -1a + 6b

Divide each side by '9'.
c = 2.333333333 + -0.1111111111a + 0.6666666667b

Simplifying
c = 2.333333333 + -0.1111111111a + 0.6666666667b

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