9(c-3)=8c-1

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Solution for 9(c-3)=8c-1 equation: 



9(c-3)=8c-1

We move all terms to the left:

9(c-3)-(8c-1)=0

We multiply parentheses

9c-(8c-1)-27=0

We get rid of parentheses

9c-8c+1-27=0

We add all the numbers together, and all the variables

c-26=0

We move all terms containing c to the left, all other terms to the right

c=26

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