9(c-4)=3(c+12)

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Solution for 9(c-4)=3(c+12) equation:


Simplifying
9(c + -4) = 3(c + 12)

Reorder the terms:
9(-4 + c) = 3(c + 12)
(-4 * 9 + c * 9) = 3(c + 12)
(-36 + 9c) = 3(c + 12)

Reorder the terms:
-36 + 9c = 3(12 + c)
-36 + 9c = (12 * 3 + c * 3)
-36 + 9c = (36 + 3c)

Solving
-36 + 9c = 36 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-36 + 9c + -3c = 36 + 3c + -3c

Combine like terms: 9c + -3c = 6c
-36 + 6c = 36 + 3c + -3c

Combine like terms: 3c + -3c = 0
-36 + 6c = 36 + 0
-36 + 6c = 36

Add '36' to each side of the equation.
-36 + 36 + 6c = 36 + 36

Combine like terms: -36 + 36 = 0
0 + 6c = 36 + 36
6c = 36 + 36

Combine like terms: 36 + 36 = 72
6c = 72

Divide each side by '6'.
c = 12

Simplifying
c = 12

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