9(c-5)=4c+5(7c-3)

Solution for 9(c-5)=4c+5(7c-3) equation:

9(c-5)=4c+5(7c-3)

We move all terms to the left:

9(c-5)-(4c+5(7c-3))=0

We multiply parentheses

9c-(4c+5(7c-3))-45=0


We calculate terms in parentheses: -(4c+5(7c-3)), so:

4c+5(7c-3)

We multiply parentheses

4c+35c-15

We add all the numbers together, and all the variables

39c-15

Back to the equation:

-(39c-15)


We get rid of parentheses

9c-39c+15-45=0

We add all the numbers together, and all the variables

-30c-30=0

We move all terms containing c to the left, all other terms to the right

-30c=30

c=30/-30

c=-1