9(d+3)=4(d-7)+

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Solution for 9(d+3)=4(d-7)+ equation: 



9(d+3)=4(d-7)+

We move all terms to the left:

9(d+3)-(4(d-7)+)=0

We multiply parentheses

9d-(4(d-7)+)+27=0



We calculate terms in parentheses: -(4(d-7)+), so:

4(d-7)+

We add all the numbers together, and all the variables

4(d-7)

We multiply parentheses

4d-28

Back to the equation:

-(4d-28)



We get rid of parentheses

9d-4d+28+27=0

We add all the numbers together, and all the variables

5d+55=0

We move all terms containing d to the left, all other terms to the right

5d=-55

d=-55/5

d=-11

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