9(d+3)=99

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Solution for 9(d+3)=99 equation:



9(d+3)=99
We move all terms to the left:
9(d+3)-(99)=0
We multiply parentheses
9d+27-99=0
We add all the numbers together, and all the variables
9d-72=0
We move all terms containing d to the left, all other terms to the right
9d=72
d=72/9
d=8

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