9(j+2)-4(3-j)=1

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Solution for 9(j+2)-4(3-j)=1 equation: 



9(j+2)-4(3-j)=1

We move all terms to the left:

9(j+2)-4(3-j)-(1)=0

We add all the numbers together, and all the variables

9(j+2)-4(-1j+3)-1=0

We multiply parentheses

9j+4j+18-12-1=0

We add all the numbers together, and all the variables

13j+5=0

We move all terms containing j to the left, all other terms to the right

13j=-5

j=-5/13

j=-5/13

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