9(j+9)-3=9(j-1)

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Solution for 9(j+9)-3=9(j-1) equation: 



9(j+9)-3=9(j-1)

We move all terms to the left:

9(j+9)-3-(9(j-1))=0

We multiply parentheses

9j-(9(j-1))+81-3=0



We calculate terms in parentheses: -(9(j-1)), so:

9(j-1)

We multiply parentheses

9j-9

Back to the equation:

-(9j-9)



We add all the numbers together, and all the variables

9j-(9j-9)+78=0

We get rid of parentheses

9j-9j+9+78=0

We add all the numbers together, and all the variables

87!=0

There is no solution for this equation

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