9(k+1)-3=2(k-5)+2

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Solution for 9(k+1)-3=2(k-5)+2 equation: 



9(k+1)-3=2(k-5)+2

We move all terms to the left:

9(k+1)-3-(2(k-5)+2)=0

We multiply parentheses

9k-(2(k-5)+2)+9-3=0



We calculate terms in parentheses: -(2(k-5)+2), so:

2(k-5)+2

We multiply parentheses

2k-10+2

We add all the numbers together, and all the variables

2k-8

Back to the equation:

-(2k-8)



We add all the numbers together, and all the variables

9k-(2k-8)+6=0

We get rid of parentheses

9k-2k+8+6=0

We add all the numbers together, and all the variables

7k+14=0

We move all terms containing k to the left, all other terms to the right

7k=-14

k=-14/7

k=-2

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