9(k+3)+2=11(k-y)

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Solution for 9(k+3)+2=11(k-y) equation:


Simplifying
9(k + 3) + 2 = 11(k + -1y)

Reorder the terms:
9(3 + k) + 2 = 11(k + -1y)
(3 * 9 + k * 9) + 2 = 11(k + -1y)
(27 + 9k) + 2 = 11(k + -1y)

Reorder the terms:
27 + 2 + 9k = 11(k + -1y)

Combine like terms: 27 + 2 = 29
29 + 9k = 11(k + -1y)
29 + 9k = (k * 11 + -1y * 11)
29 + 9k = (11k + -11y)

Solving
29 + 9k = 11k + -11y

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-11k' to each side of the equation.
29 + 9k + -11k = 11k + -11k + -11y

Combine like terms: 9k + -11k = -2k
29 + -2k = 11k + -11k + -11y

Combine like terms: 11k + -11k = 0
29 + -2k = 0 + -11y
29 + -2k = -11y

Add '-29' to each side of the equation.
29 + -29 + -2k = -29 + -11y

Combine like terms: 29 + -29 = 0
0 + -2k = -29 + -11y
-2k = -29 + -11y

Divide each side by '-2'.
k = 14.5 + 5.5y

Simplifying
k = 14.5 + 5.5y

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