9(k-2)=3(4+k)

Solution for 9(k-2)=3(4+k) equation:

9(k-2)=3(4+k)

We move all terms to the left:

9(k-2)-(3(4+k))=0

We add all the numbers together, and all the variables

9(k-2)-(3(k+4))=0

We multiply parentheses

9k-(3(k+4))-18=0


We calculate terms in parentheses: -(3(k+4)), so:

3(k+4)

We multiply parentheses

3k+12

Back to the equation:

-(3k+12)


We get rid of parentheses

9k-3k-12-18=0

We add all the numbers together, and all the variables

6k-30=0

We move all terms containing k to the left, all other terms to the right

6k=30

k=30/6

k=5