9(k-2)=3(I+4)

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Solution for 9(k-2)=3(I+4) equation: 



9(k-2)=3(+4)

We move all terms to the left:

9(k-2)-(3(+4))=0

We add all the numbers together, and all the variables

9(k-2)-(34)=0

We add all the numbers together, and all the variables

9(k-2)-34=0

We multiply parentheses

9k-18-34=0

We add all the numbers together, and all the variables

9k-52=0

We move all terms containing k to the left, all other terms to the right

9k=52

k=52/9

k=5+7/9

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