9(k-4)-k=32-2(k+)

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Solution for 9(k-4)-k=32-2(k+) equation: 



9(k-4)-k=32-2(k+)

We move all terms to the left:

9(k-4)-k-(32-2(k+))=0

We add all the numbers together, and all the variables

9(k-4)-k-(32-2(+k))=0

We add all the numbers together, and all the variables

-1k+9(k-4)-(32-2(+k))=0

We multiply parentheses

-1k+9k-(32-2(+k))-36=0



We calculate terms in parentheses: -(32-2(+k)), so:

32-2(+k)

determiningTheFunctionDomain
-2(+k)+32

We multiply parentheses

-2k+32

Back to the equation:

-(-2k+32)



We add all the numbers together, and all the variables

8k-(-2k+32)-36=0

We get rid of parentheses

8k+2k-32-36=0

We add all the numbers together, and all the variables

10k-68=0

We move all terms containing k to the left, all other terms to the right

10k=68

k=68/10

k=6+4/5

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