9(k-4)-k=32-2(k+8)

Solution for 9(k-4)-k=32-2(k+8) equation:

9(k-4)-k=32-2(k+8)

We move all terms to the left:

9(k-4)-k-(32-2(k+8))=0

We add all the numbers together, and all the variables

-1k+9(k-4)-(32-2(k+8))=0

We multiply parentheses

-1k+9k-(32-2(k+8))-36=0


We calculate terms in parentheses: -(32-2(k+8)), so:

32-2(k+8)

determiningTheFunctionDomain
-2(k+8)+32

We multiply parentheses

-2k-16+32

We add all the numbers together, and all the variables

-2k+16

Back to the equation:

-(-2k+16)


We add all the numbers together, and all the variables

8k-(-2k+16)-36=0

We get rid of parentheses

8k+2k-16-36=0

We add all the numbers together, and all the variables

10k-52=0

We move all terms containing k to the left, all other terms to the right

10k=52

k=52/10

k=5+1/5