9(k-6)-(8k+9)=3

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Solution for 9(k-6)-(8k+9)=3 equation: 



9(k-6)-(8k+9)=3

We move all terms to the left:

9(k-6)-(8k+9)-(3)=0

We multiply parentheses

9k-(8k+9)-54-3=0

We get rid of parentheses

9k-8k-9-54-3=0

We add all the numbers together, and all the variables

k-66=0

We move all terms containing k to the left, all other terms to the right

k=66

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