9(m+1)+28=8m-1

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Solution for 9(m+1)+28=8m-1 equation:



9(m+1)+28=8m-1
We move all terms to the left:
9(m+1)+28-(8m-1)=0
We multiply parentheses
9m-(8m-1)+9+28=0
We get rid of parentheses
9m-8m+1+9+28=0
We add all the numbers together, and all the variables
m+38=0
We move all terms containing m to the left, all other terms to the right
m=-38

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