9(m+1)+28=8m-1

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Solution for 9(m+1)+28=8m-1 equation: 



9(m+1)+28=8m-1

We move all terms to the left:

9(m+1)+28-(8m-1)=0

We multiply parentheses

9m-(8m-1)+9+28=0

We get rid of parentheses

9m-8m+1+9+28=0

We add all the numbers together, and all the variables

m+38=0

We move all terms containing m to the left, all other terms to the right

m=-38

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