9(m+1)+6=2(m+3)

Solution for 9(m+1)+6=2(m+3) equation:

9(m+1)+6=2(m+3)

We move all terms to the left:

9(m+1)+6-(2(m+3))=0

We multiply parentheses

9m-(2(m+3))+9+6=0


We calculate terms in parentheses: -(2(m+3)), so:

2(m+3)

We multiply parentheses

2m+6

Back to the equation:

-(2m+6)


We add all the numbers together, and all the variables

9m-(2m+6)+15=0

We get rid of parentheses

9m-2m-6+15=0

We add all the numbers together, and all the variables

7m+9=0

We move all terms containing m to the left, all other terms to the right

7m=-9

m=-9/7

m=-1+2/7