9(m-1)+6=3(m+2)+3

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Solution for 9(m-1)+6=3(m+2)+3 equation: 



9(m-1)+6=3(m+2)+3

We move all terms to the left:

9(m-1)+6-(3(m+2)+3)=0

We multiply parentheses

9m-(3(m+2)+3)-9+6=0



We calculate terms in parentheses: -(3(m+2)+3), so:

3(m+2)+3

We multiply parentheses

3m+6+3

We add all the numbers together, and all the variables

3m+9

Back to the equation:

-(3m+9)



We add all the numbers together, and all the variables

9m-(3m+9)-3=0

We get rid of parentheses

9m-3m-9-3=0

We add all the numbers together, and all the variables

6m-12=0

We move all terms containing m to the left, all other terms to the right

6m=12

m=12/6

m=2

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