9(m-7)=3(m+29)

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Solution for 9(m-7)=3(m+29) equation: 



9(m-7)=3(m+29)

We move all terms to the left:

9(m-7)-(3(m+29))=0

We multiply parentheses

9m-(3(m+29))-63=0



We calculate terms in parentheses: -(3(m+29)), so:

3(m+29)

We multiply parentheses

3m+87

Back to the equation:

-(3m+87)



We get rid of parentheses

9m-3m-87-63=0

We add all the numbers together, and all the variables

6m-150=0

We move all terms containing m to the left, all other terms to the right

6m=150

m=150/6

m=25

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