9(n+1)=(n-1)

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Solution for 9(n+1)=(n-1) equation:



9(n+1)=(n-1)
We move all terms to the left:
9(n+1)-((n-1))=0
We multiply parentheses
9n-((n-1))+9=0
We calculate terms in parentheses: -((n-1)), so:
(n-1)
We get rid of parentheses
n-1
Back to the equation:
-(n-1)
We get rid of parentheses
9n-n+1+9=0
We add all the numbers together, and all the variables
8n+10=0
We move all terms containing n to the left, all other terms to the right
8n=-10
n=-10/8
n=-1+1/4

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