9(n+1)=(n-1)

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Solution for 9(n+1)=(n-1) equation: 



9(n+1)=(n-1)

We move all terms to the left:

9(n+1)-((n-1))=0

We multiply parentheses

9n-((n-1))+9=0



We calculate terms in parentheses: -((n-1)), so:

(n-1)

We get rid of parentheses

n-1

Back to the equation:

-(n-1)



We get rid of parentheses

9n-n+1+9=0

We add all the numbers together, and all the variables

8n+10=0

We move all terms containing n to the left, all other terms to the right

8n=-10

n=-10/8

n=-1+1/4

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