9(n+1)=2(n-1)

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Solution for 9(n+1)=2(n-1) equation: 



9(n+1)=2(n-1)

We move all terms to the left:

9(n+1)-(2(n-1))=0

We multiply parentheses

9n-(2(n-1))+9=0



We calculate terms in parentheses: -(2(n-1)), so:

2(n-1)

We multiply parentheses

2n-2

Back to the equation:

-(2n-2)



We get rid of parentheses

9n-2n+2+9=0

We add all the numbers together, and all the variables

7n+11=0

We move all terms containing n to the left, all other terms to the right

7n=-11

n=-11/7

n=-1+4/7

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