9(n-4)-7n=-2(n+8)+32

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Solution for 9(n-4)-7n=-2(n+8)+32 equation:



9(n-4)-7n=-2(n+8)+32
We move all terms to the left:
9(n-4)-7n-(-2(n+8)+32)=0
We add all the numbers together, and all the variables
-7n+9(n-4)-(-2(n+8)+32)=0
We multiply parentheses
-7n+9n-(-2(n+8)+32)-36=0
We calculate terms in parentheses: -(-2(n+8)+32), so:
-2(n+8)+32
We multiply parentheses
-2n-16+32
We add all the numbers together, and all the variables
-2n+16
Back to the equation:
-(-2n+16)
We add all the numbers together, and all the variables
2n-(-2n+16)-36=0
We get rid of parentheses
2n+2n-16-36=0
We add all the numbers together, and all the variables
4n-52=0
We move all terms containing n to the left, all other terms to the right
4n=52
n=52/4
n=13

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