9(n-4)-7n=32-2(n+8(

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Solution for 9(n-4)-7n=32-2(n+8( equation: 



9(n-4)-7n=32-2(n+8(

We move all terms to the left:

9(n-4)-7n-(32-2(n+8()=0

We add all the numbers together, and all the variables

-7n+9(n-4)-(32-2(n+8()=0

We multiply parentheses

-7n+9n-(32-2(n+8()-36=0

We add all the numbers together, and all the variables

2n-(32-2(n+8()-36=0

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