9(n-4)-7n=5(3n-2)

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Solution for 9(n-4)-7n=5(3n-2) equation: 



9(n-4)-7n=5(3n-2)

We move all terms to the left:

9(n-4)-7n-(5(3n-2))=0

We add all the numbers together, and all the variables

-7n+9(n-4)-(5(3n-2))=0

We multiply parentheses

-7n+9n-(5(3n-2))-36=0



We calculate terms in parentheses: -(5(3n-2)), so:

5(3n-2)

We multiply parentheses

15n-10

Back to the equation:

-(15n-10)



We add all the numbers together, and all the variables

2n-(15n-10)-36=0

We get rid of parentheses

2n-15n+10-36=0

We add all the numbers together, and all the variables

-13n-26=0

We move all terms containing n to the left, all other terms to the right

-13n=26

n=26/-13

n=-2

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