9(q-2)=3(q-12)=

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Solution for 9(q-2)=3(q-12)= equation: 



9(q-2)=3(q-12)=

We move all terms to the left:

9(q-2)-(3(q-12))=0

We multiply parentheses

9q-(3(q-12))-18=0



We calculate terms in parentheses: -(3(q-12)), so:

3(q-12)

We multiply parentheses

3q-36

Back to the equation:

-(3q-36)



We get rid of parentheses

9q-3q+36-18=0

We add all the numbers together, and all the variables

6q+18=0

We move all terms containing q to the left, all other terms to the right

6q=-18

q=-18/6

q=-3

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