9(q-2)=3(q-122)

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Solution for 9(q-2)=3(q-122) equation: 



9(q-2)=3(q-122)

We move all terms to the left:

9(q-2)-(3(q-122))=0

We multiply parentheses

9q-(3(q-122))-18=0



We calculate terms in parentheses: -(3(q-122)), so:

3(q-122)

We multiply parentheses

3q-366

Back to the equation:

-(3q-366)



We get rid of parentheses

9q-3q+366-18=0

We add all the numbers together, and all the variables

6q+348=0

We move all terms containing q to the left, all other terms to the right

6q=-348

q=-348/6

q=-58

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