9(q-2)=3(q-2)

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Solution for 9(q-2)=3(q-2) equation: 



9(q-2)=3(q-2)

We move all terms to the left:

9(q-2)-(3(q-2))=0

We multiply parentheses

9q-(3(q-2))-18=0



We calculate terms in parentheses: -(3(q-2)), so:

3(q-2)

We multiply parentheses

3q-6

Back to the equation:

-(3q-6)



We get rid of parentheses

9q-3q+6-18=0

We add all the numbers together, and all the variables

6q-12=0

We move all terms containing q to the left, all other terms to the right

6q=12

q=12/6

q=2

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