9(q-3)=27-9q

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Solution for 9(q-3)=27-9q equation: 



9(q-3)=27-9q

We move all terms to the left:

9(q-3)-(27-9q)=0

We add all the numbers together, and all the variables

9(q-3)-(-9q+27)=0

We multiply parentheses

9q-(-9q+27)-27=0

We get rid of parentheses

9q+9q-27-27=0

We add all the numbers together, and all the variables

18q-54=0

We move all terms containing q to the left, all other terms to the right

18q=54

q=54/18

q=3

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