9(t+2)=(t-3)+15t

Solution for 9(t+2)=(t-3)+15t equation:

9(t+2)=(t-3)+15t

We move all terms to the left:

9(t+2)-((t-3)+15t)=0

We multiply parentheses

9t-((t-3)+15t)+18=0


We calculate terms in parentheses: -((t-3)+15t), so:

(t-3)+15t

We add all the numbers together, and all the variables

15t+(t-3)

We get rid of parentheses

15t+t-3

We add all the numbers together, and all the variables

16t-3

Back to the equation:

-(16t-3)


We get rid of parentheses

9t-16t+3+18=0

We add all the numbers together, and all the variables

-7t+21=0

We move all terms containing t to the left, all other terms to the right

-7t=-21

t=-21/-7

t=+3