9(t-2)=5(10t-5)

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Solution for 9(t-2)=5(10t-5) equation: 



9(t-2)=5(10t-5)

We move all terms to the left:

9(t-2)-(5(10t-5))=0

We multiply parentheses

9t-(5(10t-5))-18=0



We calculate terms in parentheses: -(5(10t-5)), so:

5(10t-5)

We multiply parentheses

50t-25

Back to the equation:

-(50t-25)



We get rid of parentheses

9t-50t+25-18=0

We add all the numbers together, and all the variables

-41t+7=0

We move all terms containing t to the left, all other terms to the right

-41t=-7

t=-7/-41

t=7/41

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