9(t-3)+3t=6(2t+2)-10

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Solution for 9(t-3)+3t=6(2t+2)-10 equation: 



9(t-3)+3t=6(2t+2)-10

We move all terms to the left:

9(t-3)+3t-(6(2t+2)-10)=0

We add all the numbers together, and all the variables

3t+9(t-3)-(6(2t+2)-10)=0

We multiply parentheses

3t+9t-(6(2t+2)-10)-27=0



We calculate terms in parentheses: -(6(2t+2)-10), so:

6(2t+2)-10

We multiply parentheses

12t+12-10

We add all the numbers together, and all the variables

12t+2

Back to the equation:

-(12t+2)



We add all the numbers together, and all the variables

12t-(12t+2)-27=0

We get rid of parentheses

12t-12t-2-27=0

We add all the numbers together, and all the variables

-29!=0

There is no solution for this equation

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