9(t-3)+6=t+19

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Solution for 9(t-3)+6=t+19 equation: 



9(t-3)+6=t+19

We move all terms to the left:

9(t-3)+6-(t+19)=0

We multiply parentheses

9t-(t+19)-27+6=0

We get rid of parentheses

9t-t-19-27+6=0

We add all the numbers together, and all the variables

8t-40=0

We move all terms containing t to the left, all other terms to the right

8t=40

t=40/8

t=5

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