9(u+2)=3(u-2)

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Solution for 9(u+2)=3(u-2) equation: 



9(u+2)=3(u-2)

We move all terms to the left:

9(u+2)-(3(u-2))=0

We multiply parentheses

9u-(3(u-2))+18=0



We calculate terms in parentheses: -(3(u-2)), so:

3(u-2)

We multiply parentheses

3u-6

Back to the equation:

-(3u-6)



We get rid of parentheses

9u-3u+6+18=0

We add all the numbers together, and all the variables

6u+24=0

We move all terms containing u to the left, all other terms to the right

6u=-24

u=-24/6

u=-4

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