9(u+2)=3u+12

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Solution for 9(u+2)=3u+12 equation: 



9(u+2)=3u+12

We move all terms to the left:

9(u+2)-(3u+12)=0

We multiply parentheses

9u-(3u+12)+18=0

We get rid of parentheses

9u-3u-12+18=0

We add all the numbers together, and all the variables

6u+6=0

We move all terms containing u to the left, all other terms to the right

6u=-6

u=-6/6

u=-1

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