9(u+3)=5u+35

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Solution for 9(u+3)=5u+35 equation: 



9(u+3)=5u+35

We move all terms to the left:

9(u+3)-(5u+35)=0

We multiply parentheses

9u-(5u+35)+27=0

We get rid of parentheses

9u-5u-35+27=0

We add all the numbers together, and all the variables

4u-8=0

We move all terms containing u to the left, all other terms to the right

4u=8

u=8/4

u=2

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