9(u+3)=5u+35

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Solution for 9(u+3)=5u+35 equation:



9(u+3)=5u+35
We move all terms to the left:
9(u+3)-(5u+35)=0
We multiply parentheses
9u-(5u+35)+27=0
We get rid of parentheses
9u-5u-35+27=0
We add all the numbers together, and all the variables
4u-8=0
We move all terms containing u to the left, all other terms to the right
4u=8
u=8/4
u=2

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