9(u-5)=7u-33

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Solution for 9(u-5)=7u-33 equation: 



9(u-5)=7u-33

We move all terms to the left:

9(u-5)-(7u-33)=0

We multiply parentheses

9u-(7u-33)-45=0

We get rid of parentheses

9u-7u+33-45=0

We add all the numbers together, and all the variables

2u-12=0

We move all terms containing u to the left, all other terms to the right

2u=12

u=12/2

u=6

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