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9(v+2)-3v=3(2v+3)-12
We move all terms to the left:
9(v+2)-3v-(3(2v+3)-12)=0
We add all the numbers together, and all the variables
-3v+9(v+2)-(3(2v+3)-12)=0
We multiply parentheses
-3v+9v-(3(2v+3)-12)+18=0
We calculate terms in parentheses: -(3(2v+3)-12), so:We add all the numbers together, and all the variables
3(2v+3)-12
We multiply parentheses
6v+9-12
We add all the numbers together, and all the variables
6v-3
Back to the equation:
-(6v-3)
6v-(6v-3)+18=0
We get rid of parentheses
6v-6v+3+18=0
We add all the numbers together, and all the variables
21!=0
There is no solution for this equation
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