9(v-2)=5(v+3)+8

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Solution for 9(v-2)=5(v+3)+8 equation: 



9(v-2)=5(v+3)+8

We move all terms to the left:

9(v-2)-(5(v+3)+8)=0

We multiply parentheses

9v-(5(v+3)+8)-18=0



We calculate terms in parentheses: -(5(v+3)+8), so:

5(v+3)+8

We multiply parentheses

5v+15+8

We add all the numbers together, and all the variables

5v+23

Back to the equation:

-(5v+23)



We get rid of parentheses

9v-5v-23-18=0

We add all the numbers together, and all the variables

4v-41=0

We move all terms containing v to the left, all other terms to the right

4v=41

v=41/4

v=10+1/4

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