9(x)=x2-8x+10

Solution for 9(x)=x2-8x+10 equation:

9(x)=x2-8x+10

We move all terms to the left:

9(x)-(x2-8x+10)=0

We add all the numbers together, and all the variables

-(+x^2-8x+10)+9x=0

We get rid of parentheses

-x^2+8x+9x-10=0

We add all the numbers together, and all the variables

-1x^2+17x-10=0

a = -1; b = 17; c = -10;
Δ = b2-4ac
Δ = 172-4·(-1)·(-10)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{249}}{2*-1}=\frac{-17-\sqrt{249}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{249}}{2*-1}=\frac{-17+\sqrt{249}}{-2}
$