9(x+1)+2x=3(x-4)+5

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Solution for 9(x+1)+2x=3(x-4)+5 equation: 



9(x+1)+2x=3(x-4)+5

We move all terms to the left:

9(x+1)+2x-(3(x-4)+5)=0

We add all the numbers together, and all the variables

2x+9(x+1)-(3(x-4)+5)=0

We multiply parentheses

2x+9x-(3(x-4)+5)+9=0



We calculate terms in parentheses: -(3(x-4)+5), so:

3(x-4)+5

We multiply parentheses

3x-12+5

We add all the numbers together, and all the variables

3x-7

Back to the equation:

-(3x-7)



We add all the numbers together, and all the variables

11x-(3x-7)+9=0

We get rid of parentheses

11x-3x+7+9=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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