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9(x+1)-4=6x+3(1+x)
We move all terms to the left:
9(x+1)-4-(6x+3(1+x))=0
We add all the numbers together, and all the variables
9(x+1)-(6x+3(x+1))-4=0
We multiply parentheses
9x-(6x+3(x+1))+9-4=0
We calculate terms in parentheses: -(6x+3(x+1)), so:We add all the numbers together, and all the variables
6x+3(x+1)
We multiply parentheses
6x+3x+3
We add all the numbers together, and all the variables
9x+3
Back to the equation:
-(9x+3)
9x-(9x+3)+5=0
We get rid of parentheses
9x-9x-3+5=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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