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9(x+1)=3(x-1)
We move all terms to the left:
9(x+1)-(3(x-1))=0
We multiply parentheses
9x-(3(x-1))+9=0
We calculate terms in parentheses: -(3(x-1)), so:We get rid of parentheses
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
9x-3x+3+9=0
We add all the numbers together, and all the variables
6x+12=0
We move all terms containing x to the left, all other terms to the right
6x=-12
x=-12/6
x=-2
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