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9(x+10)+x=2(x+3)+6
We move all terms to the left:
9(x+10)+x-(2(x+3)+6)=0
We add all the numbers together, and all the variables
x+9(x+10)-(2(x+3)+6)=0
We multiply parentheses
x+9x-(2(x+3)+6)+90=0
We calculate terms in parentheses: -(2(x+3)+6), so:We add all the numbers together, and all the variables
2(x+3)+6
We multiply parentheses
2x+6+6
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
10x-(2x+12)+90=0
We get rid of parentheses
10x-2x-12+90=0
We add all the numbers together, and all the variables
8x+78=0
We move all terms containing x to the left, all other terms to the right
8x=-78
x=-78/8
x=-9+3/4
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