9(x+2)+2=-10(x-8)-10

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Solution for 9(x+2)+2=-10(x-8)-10 equation: 



9(x+2)+2=-10(x-8)-10

We move all terms to the left:

9(x+2)+2-(-10(x-8)-10)=0

We multiply parentheses

9x-(-10(x-8)-10)+18+2=0



We calculate terms in parentheses: -(-10(x-8)-10), so:

-10(x-8)-10

We multiply parentheses

-10x+80-10

We add all the numbers together, and all the variables

-10x+70

Back to the equation:

-(-10x+70)



We add all the numbers together, and all the variables

9x-(-10x+70)+20=0

We get rid of parentheses

9x+10x-70+20=0

We add all the numbers together, and all the variables

19x-50=0

We move all terms containing x to the left, all other terms to the right

19x=50

x=50/19

x=2+12/19

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