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9(x+2)+2=-3(x-1)-11
We move all terms to the left:
9(x+2)+2-(-3(x-1)-11)=0
We multiply parentheses
9x-(-3(x-1)-11)+18+2=0
We calculate terms in parentheses: -(-3(x-1)-11), so:We add all the numbers together, and all the variables
-3(x-1)-11
We multiply parentheses
-3x+3-11
We add all the numbers together, and all the variables
-3x-8
Back to the equation:
-(-3x-8)
9x-(-3x-8)+20=0
We get rid of parentheses
9x+3x+8+20=0
We add all the numbers together, and all the variables
12x+28=0
We move all terms containing x to the left, all other terms to the right
12x=-28
x=-28/12
x=-2+1/3
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