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9(x+2)-13=3(x-3)
We move all terms to the left:
9(x+2)-13-(3(x-3))=0
We multiply parentheses
9x-(3(x-3))+18-13=0
We calculate terms in parentheses: -(3(x-3)), so:We add all the numbers together, and all the variables
3(x-3)
We multiply parentheses
3x-9
Back to the equation:
-(3x-9)
9x-(3x-9)+5=0
We get rid of parentheses
9x-3x+9+5=0
We add all the numbers together, and all the variables
6x+14=0
We move all terms containing x to the left, all other terms to the right
6x=-14
x=-14/6
x=-2+1/3
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