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9(x+2)-3=3(3x+5)
We move all terms to the left:
9(x+2)-3-(3(3x+5))=0
We multiply parentheses
9x-(3(3x+5))+18-3=0
We calculate terms in parentheses: -(3(3x+5)), so:We add all the numbers together, and all the variables
3(3x+5)
We multiply parentheses
9x+15
Back to the equation:
-(9x+15)
9x-(9x+15)+15=0
We get rid of parentheses
9x-9x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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