9(x+2)-3=6(2x-5)+7x

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Solution for 9(x+2)-3=6(2x-5)+7x equation: 



9(x+2)-3=6(2x-5)+7x

We move all terms to the left:

9(x+2)-3-(6(2x-5)+7x)=0

We multiply parentheses

9x-(6(2x-5)+7x)+18-3=0



We calculate terms in parentheses: -(6(2x-5)+7x), so:

6(2x-5)+7x

We add all the numbers together, and all the variables

7x+6(2x-5)

We multiply parentheses

7x+12x-30

We add all the numbers together, and all the variables

19x-30

Back to the equation:

-(19x-30)



We add all the numbers together, and all the variables

9x-(19x-30)+15=0

We get rid of parentheses

9x-19x+30+15=0

We add all the numbers together, and all the variables

-10x+45=0

We move all terms containing x to the left, all other terms to the right

-10x=-45

x=-45/-10

x=4+1/2

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